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Home/ Questions/Q 6697065
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T06:24:57+00:00 2026-05-26T06:24:57+00:00

I am generating a random number and checking if the character contained is a

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I am generating a random number and checking if the character contained is a certain character (i.e. 0xDB). This doesn’t seem to be the correct way to do it as it seems like my if() is always false and goes to else.

How can I achieve this? Code below. Thanks!

if(buffer[randomNumber] == 0xDB) 
    count++;
else {
    buffer[randomNumber] = 0xDB;
    arrayChangeFlag++;
    count++;
}
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  1. Editorial Team
    Editorial Team
    2026-05-26T06:24:57+00:00Added an answer on May 26, 2026 at 6:24 am

    What is the type of buffer?

    I guess that it is either signed char or implicitly-signed char. The range of a signed char in most implementations is (-128,+127). 0xDB is outside that range, so that equality test might never be true.

    Try changing the type of buffer to unsigned char, or replacing your test with:

     if((unsigned char)buffer[randomNumber] == 0xDB) 
    

    or

     if(buffer[randomNumber] == (char)0xDB) 
    
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