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Home/ Questions/Q 8618341
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T06:05:05+00:00 2026-06-12T06:05:05+00:00

I am getting an invalid argument error with this code. Please help me fix

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I am getting an “invalid argument” error with this code. Please help me fix it.

$sub1 = "sub1";
$sub2 = "sub2";
$td = "4";
foreach (glob("directory/".$sub1."/".$sub2."*.td".$td) as $filename) { //This is the line throwing the error
    echo "$filename size " . filesize($filename) . "\n"; //This is right from php.net manual
}
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  1. Editorial Team
    Editorial Team
    2026-06-12T06:05:06+00:00Added an answer on June 12, 2026 at 6:05 am

    It looks like you’re missing a slash:

    foreach (glob("directory/".$sub1."/".$sub2."*.td".$td) as $filename)
    

    Should be:

    foreach (glob("directory/".$sub1."/".$sub2."/*.td".$td) as $filename)
    

    (If I’ve got a variable that’s storing a directory, I always add the slash on the end – it keeps things consistent, and means I don’t need to remember to cat a slash back on when I’m using it.)

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