Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6542021
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T11:10:32+00:00 2026-05-25T11:10:32+00:00

I am getting back two rows from my query, I tested it in phpadmin.

  • 0

I am getting back two rows from my query, I tested it in phpadmin.

In firebug I can only see the data from one row.

What could be wrong that I don’t see?

$data = mysql_fetch_assoc($r);

        }
    }

    header('Content-type: application/json');           
    $output = array(
    "check" => $check,
    "users" => $data,
    "testnumberoffrows" => $number
    );

    echo json_encode($output);

in the ajaxfunction

if( data.check ){
    var user = data.users;
    console.log(user);

thanks, Richard

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T11:10:33+00:00Added an answer on May 25, 2026 at 11:10 am

    mysql_fetch_assoc() fetches only one row. You need to loop until it returns FALSE, building up an output array.

    Something like this:

    while (($row = mysql_fetch_assoc($r)) !== FALSE) {
        $data[] = $row;
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm trying to figure out a clean way of getting data back from my
I am getting back a string[] from a 3rd party library. I want to
I'm getting back from a library what looks to be an incorrect unicode string:
I took a hiatus from C and am just getting back into it again.
I am getting an object back from ASP.NET, and when tracing the XML it
I am getting back into a bit more .NET after a few-years of not
I'm slowly getting back into PHP, and now I run into a problem, I
I'm just getting back into C++ after a couple of years of doing a
I'm getting back into .NET after numerous years in PHP/MySQL back in 2002 on
I'm getting back into .NET development after a couple years and it seems that

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.