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Home/ Questions/Q 6026499
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T04:27:14+00:00 2026-05-23T04:27:14+00:00

I am getting following exception with my code You have an error in your

  • 0

I am getting following exception with my code

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''MachineSimulator'' 

var sqlParams = new[]
                                            {
                                                new MySqlParameter("@MachineSimulatorDb",GlobalVariables.MachineSimulatorDb),
                                                new MySqlParameter("@CAMXMassagesTable" ,GlobalVariables.CamxmassagesTable)
                                            };

            using (var conn = new MySqlConnection(GlobalVariables.ConnectionString))
            {
                conn.Open();
                using(var command = new MySqlCommand())
                {
                    command.Connection = conn;
                    command.Parameters.AddRange(sqlParams);

                    command.CommandText = "CREATE DATABASE IF NOT EXISTS @MachineSimulatorDb;";

                    command.ExecuteNonQuery();


                }


            }

Any idea what is wrong there ?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-23T04:27:15+00:00Added an answer on May 23, 2026 at 4:27 am

    MySQL probably doesn’t allow you to pass a parameter to create database. Try:

    command.CommandText = string.Format("CREATE DATABASE IF NOT EXISTS `{0}`",  
        GlobalVariables.MachineSimulatorDb);
    

    If the variables you use come from an usafe source, you should be aware of the danger of SQL Injection.

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