Question

I am getting output of reshape function as follow

s1 =

11 
00 
10 
11 
01 
11 
10 
10 
10 
10 
10 
10 
10 
01 
10 
01

How to convert s1 as

[1 1 0 0 1 0 1 1 0 1 1 1 1 0 1 0 1 0 1 0 1 0 1 0 1 0 0 1 1 0 0 1] 

so i can pick up bit values
s1(1) will be 1
s1(3) will be 0
s1(5) will be 1

I have tried it with reshape and transpose but not picking up correct bit values. Appreciate any help..

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I am doing following operation with below code

converting cipher text to bytes, then I am calculating index variable (called as p) & formula is MOD(No of Bytes,3).. I have ciphertext length as 5 bytes so Index Variable (p) is 2.. I will always have index varaible values as 0 or 1 or 2 which will be based on no. of Bytes

Say ciphertext is 11001011 01111010 10101010 10011001 01010101

This data is five bytes there for inde variable is 2

11001011 01111010 10101010 10011001 01010101

Now
for first two bits (11) , index variable to be assigned as 2
for next two bits (00), index variable to be assigned as 0
for next two bits (10), index variable to be assigned as 1
for next two bits (11), index variable to be assigned as 2..so on till end of my bits.

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Other Example
Ciphertet with Three Bytes 11001011 01111010 10101010
Index Variable (p) will be 0

for first two bits (11) , index variable to be assigned as 0
for next two bits (00), index variable to be assigned as 1
for next two bits (10), index variable to be assigned as 2
for next two bits (11), index variable to be assigned as 0..
so on till end of my bits..

s = '11001011 01111010 10101010 10011001 01010101'
p = rem(numel(regexp(s,' [01]'))+1,3)
k = (0:2)'
s1 = reshape(regexprep(s,' ',''),2,[])'
n = size(s1,1)
N = k(:,ones(fix((n+1)/3)+1,1))
P = N(find(N(:,1) == p)+(0:n-1))'

Answer 1

Well s1' will give you

[11 00 10 11 ...]

but if you show us the input to your function I might be able to give you the answer you really want.