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Home/ Questions/Q 8703881
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T02:57:58+00:00 2026-06-13T02:57:58+00:00

I am getting strange behaviour from this function. Input public function fetch_array($result_set) { $rows

  • 0

I am getting strange behaviour from this function.

Input

    public function fetch_array($result_set) 
{
        $rows = array();
        while ($row = mysql_fetch_array($result_set)) 
        {
            $rows[] = $row;
            print_r($row);
            break;
        }
        return $rows;

}

I have made the function run once but it its duplicating a row from my MySQL query result.

Output

Array ( [0] => Sarah [first_name] => Sarah [1] => Palin [second_name] => Palin ) 

It should be

Correct Output

Array ( [first_name] => Sarah [second_name] => Palin ) 

I used this SO question example

Use mysql_fetch_array() with foreach() instead of while()

Not my query or Mysql result fault

https://i.stack.imgur.com/icUYI.png

enter image description here


What is going wrong here?

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  1. Editorial Team
    Editorial Team
    2026-06-13T02:58:00+00:00Added an answer on June 13, 2026 at 2:58 am

    This is not an error, it’s the intended behavior of mysql_fetch_array() http://us.php.net/manual/en/function.mysql-fetch-array.php

    You can either set the result_type flag, or you can just use mysql_fetch_assoc() instead. http://us.php.net/manual/en/function.mysql-fetch-assoc.php

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