Question

I am getting the values of posted data with php.

I am using:

if (isset($_POST['fieldname'])) {
$field1 = $_POST['fieldname'];
}

This works correctly and I can return the value using:

echo $field1;

My problem is that there is a field called ul_image which contains the name of an image and it’s for upload.

I’ve tried:

if (isset($_POST['ul_image'])) {
$field2 = $_POST['ul_image'];
}

echo $field2;

but this returns nothing.

I’m out of ideas so does anyone have any suggestions?

Answer 1

The file data is contained in $_FILES['ul_image']. It contains an array with the following keys: name (original filename), type (MIME type), size (file size in bytes), tmp_name (temporary path on your server), error (any errors).

Then to store the file permanently use move_uploaded_file($_FILES['ul_image']['tmp_name'], $destination). The reason is added security; this function makes sure a hacker has not manipulated your script to move arbitrary files on your server.