Question

i am getting this data from my database and unserlialzing them for my use and want to display the output from these details

a:3:{s:8:"firstid";s:9:"photo1977";s:3:"secondid";s:16:"photos/view/1977";s:5:"thirdid";a:1:{i:0;s:40:"uploads/userfiles/201205/09_34_bqqi9.png";}}

everything is working as expected except the thirdid . which is giving the output as Array

i am using

$firstid = $arr['firstid'];
$secondid = $arr['secondid'];
$thirdid = $arr['thirdid'];

to display the output . i am getting the output of firstid & secondid just fine but thirdid output i am not getting.

Answer 1

$arr['thirdid] is an array itself, so $thirdid holds an array. Try

$thirdid = $arr['thirdid'][0];

to get the file path or

print_r($arr['thirdid']);

to output the array.

Updated.