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Home/ Questions/Q 7609411
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Editorial Team
  • 0
Editorial Team
Asked: May 31, 20262026-05-31T01:09:53+00:00 2026-05-31T01:09:53+00:00

I am getting this error when my form is completed, despite the fact that

  • 0

I am getting this error when my form is completed, despite the fact that the successful response is correctly displayed and the item is added to the database.

Here’s the error

Warning: mysql_free_result(): supplied argument is not a valid MySQL result resource in /home/site4/public_html/lab/mailinglist/mailing_list_external.php on line 18

Line 18 is

mysql_free_result($check_res);

and the entire PHP file is

    <?php
include("mailing_list_include.php");
// determine if they need to see the form or not

if ($_POST["email"] == "") {
    header("Location: mailing_list_external.php");
    exit;
} else {
    // connect to database
    doDB();

    // check that the email is in list
    emailChecker($_POST["email"]);

    // get number of results and do action
    if (mysqli_num_rows($check_res) < 1) {
        // free result
        mysql_free_result($check_res); 

        // add record
        $add_sql =  "INSERT INTO subscribers (email)
                    VALUES('".$_POST["email"]."')";
        $add_res =  mysqli_query($mysqli, $add_sql)
                    or die(mysqli_error($mysqli));
        $display_block = "<p>Thanks for signing up!</p>";

        // close connection to mysql
        mysqli_close($mysqli);
    } else {
        // print failure message
        $display_block = "<p>You're already subscribed!</p>";

    }
}
?>
<html>
<body>
<?php echo "$display_block"; ?>
</body>
</html>

Like I said, it works fine but I still get this error…

Here’s the code for the included file (mailing_list_include.php)

    <?php

function doDB() {
global $mysqli;

// connect to server and select database; you may need it
$mysqli = mysqli_connect("localhost", "XXX",
    "XXX", "XXX");

    // if connection fails, stop script execution
    if (mysqli_connect_errno()) {
        printf("Connect failed: %s\n", mysqli_connect_error());
        exit();
}
}

function emailChecker($email) {
global $mysqli, $check_res;

//check that email is not already in list
$check_sql = "SELECT id FROM subscribers
    WHERE email = '".$email."'";
$check_res = mysqli_query($mysqli, $check_sql)
    or die(mysqli_error($mysqli));
}
?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T01:09:54+00:00Added an answer on May 31, 2026 at 1:09 am

    Use mysqli_free_result – I suspect it’s because you’re using mysql_free_result, which is a different library

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