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Home/ Questions/Q 9169921
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T15:56:43+00:00 2026-06-17T15:56:43+00:00

I am getting this warning: warning: [static] static method should be qualified by type

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I am getting this warning: warning: [static] static method should be qualified by type name, AnchorPane, instead of by an expression

here is my code:

public Chart(Vector<String[]> v, final Pane p, final AnchorPane ap){
    super();
    this.v = v;
    p.heightProperty().addListener(new ChangeListener<Number>() {
        public void changed(ObservableValue<? extends Number> ov,
        Number old_val, Number new_val) {
            draw();

            System.out.println(heightProperty().doubleValue()+" "+ap.getBottomAnchor(p));

        }
    });
}
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  1. Editorial Team
    Editorial Team
    2026-06-17T15:56:44+00:00Added an answer on June 17, 2026 at 3:56 pm

    AnchorPane.getBottomAnchor() is a static method. Static methods are associated with a class, not an instance, and should therefore be called by their class name, not through a reference. The reason is to avoid confusion about which method is finally called, since static methods can not be overridden. See also https://stackoverflow.com/a/2629846/1611055 for some good additional information.

    Try

    System.out.println(heightProperty().doubleValue()+" "+AnchorPane.getBottomAnchor(p));
    
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