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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T15:48:16+00:00 2026-06-11T15:48:16+00:00

I am getting three different results in the following queries, they all have same

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I am getting three different results in the following queries, they all have same joins & column to count just a condition to count is different, is there any way so that I could get the Questions, Correct, Attempted & IeslTopics.Name columns together in a single query?

SELECT     COUNT(TestResults2.QuestionID) AS Questions, Topics.Name
FROM         TestResults 
INNER JOIN   TestResults2 ON TestResults.ID = TestResults2.TestResultID 
INNER JOIN   QuestionBank ON TestResults2.QuestionID = QuestionBank.ID 
INNER JOIN   Topics ON QuestionBank.TopicID = Topics.ID
WHERE        (TestResults.StudentID = 1) AND (TestResults.ID = 46)
GROUP BY   Topics.Name
//All topic

SELECT     COUNT(TestResults2.QuestionID) AS Correct, Topics.Name
FROM         TestResults 
INNER JOIN   TestResults2 ON TestResults.ID = TestResults2.TestResultID 
INNER JOIN   QuestionBank ON TestResults2.QuestionID = QuestionBank.ID AND 
                             TestResults2.Answer = QuestionBank.Answer 
INNER JOIN   Topics ON QuestionBank.TopicID = Topics.ID
WHERE        (TestResults.StudentID = 1) AND (TestResults.ID = 46)
GROUP BY   Topics.Name
//Correct topic

SELECT     COUNT(TestResults2.QuestionID) AS Attempted, Topics.Name
FROM         TestResults 
INNER JOIN   TestResults2 ON TestResults.ID = TestResults2.TestResultID 
INNER JOIN   QuestionBank ON TestResults2.QuestionID = QuestionBank.ID AND 
                             TestResults2.Answer <> '\0' 
INNER JOIN   Topics ON QuestionBank.TopicID = Topics.ID
WHERE        (TestResults.StudentID = 1) AND (TestResults.ID = 46)
GROUP BY   Topics.Name
//Attempted topic
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T15:48:17+00:00Added an answer on June 11, 2026 at 3:48 pm

    You can use a conditional inside a SUM to supply ones for items that you are looking for and zeros for other items, like this:

    SELECT
        COUNT(TestResults2.QuestionID) AS Questions
    ,   SUM(CASE WHEN TestResults2.Answer = QuestionBank.Answer THEN 1 ELSE 0 END) AS Correct
    ,   SUM(CASE WHEN TestResults2.Answer <> '\0' THEN 1 ELSE 0 END) AS Attempted
    ,   Topics.Name
    FROM         TestResults INNER JOIN
                      TestResults2 ON TestResults.ID = TestResults2.TestResultID INNER JOIN
                      QuestionBank ON TestResults2.QuestionID = QuestionBank.ID INNER JOIN
                      Topics ON QuestionBank.TopicID = Topics.ID
    WHERE     (TestResults.StudentID = 1) AND (TestResults.ID = 46)
    GROUP BY Topics.Name
    
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