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Home/ Questions/Q 8150621
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T15:07:19+00:00 2026-06-06T15:07:19+00:00

I am graphing several columns of a large array of data (through numpy.genfromtxt) against

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I am graphing several columns of a large array of data (through numpy.genfromtxt) against an equally sized time column. Missing data is often referred to as nan, -999, -9999, etc. However I can’t figure out how to remove multiple values from the array. This is what I currently have:

for cur_col in range(start_col, total_col):
    # Generate what is to be graphed by removing nan values
    data_mask = (file_data[:, cur_col] != nan_values)
    y_data = file_data[:, cur_col][data_mask]
    x_data = file_data[:, time_col][data_mask]

After which point I use matplotlib to create the appropriate figures for each column. This works fine if the nan_values is a single integer, but I am looking to use a list.

EDIT: Here is a working example.

import numpy as np

file_data = np.arange(12.0).reshape((4,3))
file_data[1,1] = np.nan
file_data[2,2] = -999
nan_values = -999

for cur_col in range(1,3):
    # Generate what is to be graphed by removing nan values
    data_mask = (file_data[:, cur_col] != nan_values)
    y_data = file_data[:, cur_col][data_mask]
    x_data = file_data[:, 0][data_mask]
    print 'y: ' + str(y_data)
    print 'x: ' + str(x_data)
print file_data

>>> y: [  1.  nan   7.  10.]
    x: [ 0.  3.  6.  9.]
    y: [  2.   5.  11.]
    x: [ 0.  3.  9.]
    [[   0.    1.    2.]
    [   3.   nan    5.]
    [   6.    7. -999.]
    [   9.   10.   11.]]

This will not work if nan_values = [‘nan’, -999] which is what I am looking to accomplish.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T15:07:20+00:00Added an answer on June 6, 2026 at 3:07 pm

    I would suggest using masked arrays like so:

    >>> a = np.arange(12.0).reshape((4,3))
    >>> a[1,1] = np.nan
    >>> a[2,2] = -999
    >>> a
    array([[   0.,    1.,    2.],
           [   3.,   nan,    5.],
           [   6.,    7., -999.],
           [   9.,   10.,   11.]])
    >>> m = np.ma.array(a,mask=(~np.isfinite(a) | (a == -999)))
    >>> m
    masked_array(data =
     [[0.0 1.0 2.0]
     [3.0 -- 5.0]
     [6.0 7.0 --]
     [9.0 10.0 11.0]],
                 mask =
     [[False False False]
     [False  True False]
     [False False  True]
     [False False False]],
           fill_value = 1e+20)
    
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