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Home/ Questions/Q 6722751
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Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T09:29:03+00:00 2026-05-26T09:29:03+00:00

I am have this query below that is a drop down for year (from

  • 0

I am have this query below that is a drop down for year (from 1900-current). I am using a $variable to show a previously chosen year first in the drop down for an edit form. It works except that for all other years 2011 is also repeated with them. How do i tweak it so that $y shows first and then all years underneath that?

Code:

    <select name="year">
<?PHP for($i=date("1900"); $i<=date("2011"); $i++)
        if($year == $i)
            echo "<option value='$y' selected>$y</option>
     <option value='$i' selected>$i</option>";
        else
            echo "<option value='$y' selected>$y</option>
     <option value='$i'>$i</option>";
?>
    </select></td>
    </tr> 
  • 1 1 Answer
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T09:29:04+00:00Added an answer on May 26, 2026 at 9:29 am

    Keep it simple:

        <select name="year">
            <?php for($i=1900; $i<=date('Y'); $i++) {
            if($i == date('Y'))
                echo "<option value='$i' selected='selected'>$i</option>";
            else
                echo "<option value='$i'>$i</option>";
            }
    ?>
        </select></td>
        </tr> 
    

    Or even better:

    <select name="year">
        <?php for($i=1900; $i<=date('Y'); $i++)
            echo "<option value='$i' ".(($i == date('Y')?'selected="selected"':'')).">$i</option>";
        ?>
    </select></td>
    </tr> 
    

    And backwards

    <select name="year">
        <?php for($i=date('Y'); $i>=1900; $i--)
            echo "<option value='$i' ".(($i == date('Y')?'selected="selected"':'')).">$i</option>";
        ?>
    </select></td>
    </tr> 
    
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