Question

I am having a bit of difficulty working something out. I have the follow 2 tables:

fixture
id, hometeam, awayteam, datetime

feed
id, homeodd, drawodd, awayodd fixtureid

In the feed table fixtureid is the same as the id column in the fixture table. the issue I’m having is only 10 fixtures have a homeodd or drawodd or awayodd but I still want to show all the fixtures and just show the data from homeodd/drawodd/awayodd if its available.

So far I have got it to the following statement but its only pulling through matches that have a feed fixtureid matched to it:

SELECT fixture.id, hometeam, awayteam, datetime, feed.fixtureid AS fix_id, feed.homeodd, feed.drawodd, feed.awayodd FROM fixture JOIN feed feed ON feed.fixtureid = fixture.id

Like I said this only returns 10 options instead of the 360 available, as it looks like its just pulling out data that has a match in the feed table.

Any ideas how I could achieve all the fixtures and just show the data if its in the table?

Answer 1

You simply need a LEFT JOIN – this will give you all the rows on the ‘left’ table, and NULLs where there is no corresponding row in the ‘right’ table:

SELECT fixture.id, hometeam, awayteam, datetime, feed.fixtureid AS fix_id, 
       feed.homeodd, feed.drawodd, feed.awayodd 
FROM fixture 
LEFT JOIN feed feed ON (feed.fixtureid = fixture.id)