Question

I am having a brain freeze with what originally I thought would be a simple query.

I have a table like the following:

ID   DETAILID    NAME    
-------------------------------------------------
1    1           Sed ut perspiciatis unde
2    1           omnis iste natus error
3    1           sit voluptatem accusantium
4    1           doloremque laudantium
5    2           totam rem aperiam
6    2           labore et dolore
7    3           voluptate velit esse
8    3           occaecati cupiditate non
9    3           culpa qui officia
10   3           placeat facere possimus
11   3           Nam libero tempore

I want to search the NAME field multiple times with LIKE ‘%%’ (number of LIKE’s will be random) but I only want to return a distinct DETAILID where the LIKE’s are all found in records where the DETAILID is the same.

I am going round in circles and getting nowhere fast. Can anybody help?

Answer 1

This query gives you the DETAILIDs that match all the LIKE conditions

SELECT DETAILID
FROM
(
    select DETAILID, 1 as WhichMatch
    from tbl
    where NAME LIKE '%a%'
    UNION ALL
    select DETAILID, 2 as WhichMatch
    from tbl
    where NAME LIKE '%b%'
    UNION ALL
    select DETAILID, 3 as WhichMatch
    from tbl
    where NAME LIKE '%c%'
) SQ
GROUP BY DETAILID
HAVING COUNT(DISTINCT WhichMatch) = 3