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Home/ Questions/Q 7649483
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T10:58:40+00:00 2026-05-31T10:58:40+00:00

I am having a file named build.ps1 where there is a function called Execute-build

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I am having a file named “build.ps1” where there is a function called “Execute-build” available.

I am calling that function from another file named “Dailybuild.ps1” like below.

. ./Build.ps1

# starting different jobs (parallel processing)
$job1 = Start-Job { Execute-Build "List.txt" }
$job2 = Start-Job { Execute-Build "List2.txt" }


# synchronizing all jobs, waiting for all to be done
Wait-Job $job1, $job2

# receiving all results
Receive-Job $job1, $job2

# cleanup
Remove-Job $job1, $job2

But i am receiving error like follows

Receive-Job : The term ‘Execute-Build’ is not recognized as the name
of a cmdle t, function, script file, or operable program. Check the
spelling of the name, or if a path was included, verify that the path
is correct and try again.

Why this error occurs and how to resolve this?

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  1. Editorial Team
    Editorial Team
    2026-05-31T10:58:41+00:00Added an answer on May 31, 2026 at 10:58 am

    The dot sourced code will not be available in the background job.

    One way to solve this is to dot source Build.ps1 in the background job like this:

    $job1 = Start-Job { 
        . "C:\Path\To\Build.ps1"
        Execute-Build "List.txt" 
    }
    

    You can also pass the path as a parameter like this:

    $path = (Resolve-Path ./Build.ps1).Path
    $job1 = Start-Job {
        param ($ScriptPath)
        . "$ScriptPath"
        Execute-Build "List.txt" 
    } -ArgumentList $path
    
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