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Home/ Questions/Q 3754616
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T09:34:20+00:00 2026-05-19T09:34:20+00:00

I am having a problem trying to get the orientation of the device correct.

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I am having a problem trying to get the orientation of the device correct. I have to show an action sheet that should come depending on the orientation of the device. Here is the code I am using.

UIDeviceOrientation orientation = [UIDevice currentDevice].orientation;

  switch (orientation) 

  {
   case UIDeviceOrientationPortrait:
   case UIDeviceOrientationFaceUp:
   case UIDeviceOrientationFaceDown: 
   case UIDeviceOrientationUnknown:
   case UIDeviceOrientationPortraitUpsideDown:

   [self displayActionSheetInPotraitMode];
   break;

   case UIInterfaceOrientationLandscapeLeft:
   case UIInterfaceOrientationLandscapeRight:

   [self displayActionSheetInLandscapeMode];
   break;

   default:

   [self displayActionSheetInPotraitMode];
   break;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T09:34:21+00:00Added an answer on May 19, 2026 at 9:34 am

    Let’s look what the UIDevice Class Reference tells us about the orientation property.

    The value of this property always returns 0 unless orientation notifications have been enabled by calling beginGeneratingDeviceOrientationNotifications.

    So, you should call

    [[UIDevice currentDevice] beginGeneratingDeviceOrientationNotifications]
    

    somewhere earlier in your code.


    Also, I’d like to suggest a way to simplify your current code:

    UIDeviceOrientation orientation = [UIDevice currentDevice].orientation;
    
    if (UIDeviceOrientationIsLandscape(orientation)) {
        [self displayActionSheetInLandscapeMode];
    } else {
        [self displayActionSheetInPotraitMode];
    }
    
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