Question

I am having a problem with a while loop in c++. The while loop is always being executed the first time around but when the program reaches the cin of the while loop the while loop works perfectly I was wondering what I was doing wrong. Thanks in advance. Also I am sorry if the problem is noobish. I am still a beginner.

cout<<"Would you like some ketchup? y/n"<<endl<<endl<<endl; //Ketchup
selection screen
cin>>optketchup;



while (optketchup != "yes" && optketchup != "no" && optketchup != "YES" && optketchup != "Yes"  && optketchup != "YEs"  && optketchup != "yEs"  && optketchup != "YeS"
     && optketchup != "yeS" &&  optketchup != "YeS"  && optketchup != "yES" && optketchup != "y"  && optketchup != "Y"  && optketchup != "No"  && optketchup != "nO"
      && optketchup != "NO"  && optketchup != "n"  && optketchup != "No");
{

    cout<<"You have entered an entered "<<optketchup<<" which is an invalid
 option. Please try again."<<endl;
    cin>>optketchup;

}


if (optketchup == "yes" || optketchup == "YES" || optketchup == "Yes"  || optketchup == "YEs"  || optketchup == "yEs"  || optketchup == "YeS"
     || optketchup == "yeS" ||  optketchup == "YeS"  || optketchup == "yES" || optketchup == "y"  || optketchup == "Y")
{
    slcketchup == "with";
}
else
{
    slcketchup == "without";
}

cout<<"Your sandwich shall be "<<slcketchup<<" ketchup."<<endl;



system ("pause");

Again thanks in advance.

Answer 1

You have a semicolon(‘;’) in the while. That’s causing the problem.

Don’t write

while(.... lots of conditions ...);
{
    //stuff
}

Write

while(.... lots of conditions ...)
{
    //stuff
}

Notice the lack of the ; in the 2nd one.

Other than that, what if you had to check for the word Pneumonoultramicroscopicsilicovolcanoconiosis. How many combinations of upper & lower cases would you end up checking?
Instead, convert the input into upper case & compare against upper case YES or NO or PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS.