Question

I am having an issue getting the results I want from my SQL statement. I know I’m probably missing something simple but I just can’t see it.

Here are my tables.

Table: Users (RoleID is linked to ID in Roles Table)
ID,   FirstName,   LastName,   RoleID 
1,    Matt,        Ryan,       1
2,    Chipper,     Jones,      1
3,    Julio,       Jones,      2
4,    Jason,       Bourn,      3

Table: Roles
ID,    Name
1,     Field Rep
2,     Tech
3,     Admin

Table: FRrequests (UserID is linked to ID in Users table) 
ID,   UserID,    Status
1,    1,         Open
2,    1,         Submitted
3,    1,         Delayed
4,    1,         Complete

What I want is an SQL statement that shows me a count of all the “Submitted” & “Delayed” requests for all the Field Reps. Below is an example of desired results.

Name             Count
Chipper Jones    0
Matt Ryan        2

Here is the statement I have so far and the results it gives me.

SELECT Users.FirstName + ' ' + Users.LastName AS Name, COUNT(FRrequests.ID) AS 'Open Requests'
FROM Users INNER JOIN
          Roles ON Users.RoleID = Roles.ID LEFT OUTER JOIN
          FRrequests ON Users.ID = FRrequests.UserID
WHERE (Roles.Name = N'Field Rep') AND (FRrequests.Status = 'Submitted' OR FRrequests.Status = 'Delayed')
GROUP BY Users.FirstName, Users.LastName

Name             Count
Matt Ryan        2

I know that the “AND (FRrequests.Status = ‘Submitted’ OR FRrequests.Status = ‘Delayed’)” part is what is breaking it. If I run it without that in the statement I get all the users but it counts all status not just submitted and delayed. I just can’t figure out what I’m missing to get this to work. Any help would be greatly appreciated.

Answer 1

You are really close, try the following:

SELECT U.FirstName + ' ' + U.LastName AS Name, COUNT(F.ID) AS 'Open Requests'
FROM Users U
INNER JOIN Roles R
    ON U.RoleID = R.ID 
LEFT JOIN ( SELECT * FROM FRrequests 
            WHERE Status IN ('Submitted','Delayed')) F
    ON U.ID = F.UserID
WHERE R.Name = N'Field Rep' 
GROUP BY U.FirstName, U.LastName