Question

I am having problems calling a URL from PHP code. I need to call a service using a query string from my PHP code. If I type the URL into a browser, it works ok, but if I use file-get-contents() to make the call, I get:

Warning: file-get-contents(http://…. ) failed to open stream: HTTP request failed! HTTP/1.1 202 Accepted in …

The code I am using is:

$query=file_get_contents('http://###.##.##.##/mp/get?mpsrc=http://mybucket.s3.amazonaws.com/11111.mpg&mpaction=convert format=flv'); echo($query); 

Like I said – call from the browser and it works fine. Any suggestions?

I have also tried with another URL such as:

$query=file_get_contents('http://www.youtube.com/watch?v=XiFrfeJ8dKM'); 

This works fine… could it be that the URL I need to call has a second http:// in it?

Answer 1

Try using cURL.

<?php  $curl_handle=curl_init(); curl_setopt($curl_handle, CURLOPT_URL,'http://###.##.##.##/mp/get?mpsrc=http://mybucket.s3.amazonaws.com/11111.mpg&mpaction=convert format=flv'); curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 2); curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1); curl_setopt($curl_handle, CURLOPT_USERAGENT, 'Your application name'); $query = curl_exec($curl_handle); curl_close($curl_handle);  ?>