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Home/ Questions/Q 6752747
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Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T13:04:52+00:00 2026-05-26T13:04:52+00:00

I am having problems which the following code: if(mysql_num_rows(mysql_query(SELECT user_id FROM myTable WHERE user_id

  • 0

I am having problems which the following code:

if(mysql_num_rows(mysql_query("SELECT user_id FROM myTable WHERE user_id = '$user_id'"))){

    mysql_query("UPDATE myTable SET
    id='',
    user_id='$user_id',
    title='$title',
    WHERE user_id='$user_id'
    ") 

}  else {

    mysql_query("INSERT INTO myTable (id, user_id, title)
                 VALUES ('', $user_id, $title) ");
}

The update part seems to work but after the else it doesn’t insert the record into the table.

Can anyone spot what could be the problem please?

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:04:53+00:00Added an answer on May 26, 2026 at 1:04 pm

    I am having problems which the following code

    no wonder, as this code is just horrible. four nested operators!
    even if you’d get some error messages, you’ll be unable to tell what operator it belongs to

    no errors reported either

    you didn’t ask for any

    make your code more consistent and add error reporting to it:

    $sql = "SELECT user_id FROM myTable WHERE user_id = '$user_id'";
    $res = mysql_query($sql) or trigger_error(mysql_error()." ".$sql);
    if (mysql_num_rows($res)) { 
      $sql = "UPDATE myTable SET id='',user_id='$user_id',title='$title', WHERE user_id='$user_id'";
      mysql_query($sql) or trigger_error(mysql_error()." ".$sql); 
    }  else { 
      $sql = "INSERT INTO myTable (id, user_id, title) VALUES ('', $user_id, $title)";
      mysql_query($sql) or trigger_error(mysql_error()." ".$sql); 
    }
    

    and you will always be informed of the any error occurred

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