Question

I am having problems with this code:

<?php
$new_value = 'testing';

$con = mysql_connect("localhost","user","pass");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("my_db", $con);

mysql_query("INSERT INTO myDB (myField) VALUES ('$new_value')");

mysql_close($con);

?>

2 issues are happening:

1st – 2 records are being inserted instead of 1

2nd – $new_value is not changed and it’s creating multiple instances with the same $new_value value when I only want 1.

Answer 1

I think this is something similar to what you are after, after reading your comment:

INSERT IGNORE INTO tablename (fields)
VALUES(values);

Use INSERT IGNORE rather than INSERT. If a record doesn’t duplicate an existing record, MySQL inserts it as usual. If the record is a duplicate, the IGNORE keyword tells MySQL to discard it silently without generating an error.

edit
Or as Vytautas points out; if you want to replace the value use REPLACE in stead of INSERT