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Asked: 2026-05-29T05:08:56+00:00

I am having some difficulty using PHP with jQTouch. I am fairly confident with

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I am having some difficulty using PHP with jQTouch.
I am fairly
confident with JavaScript however my PHP skills are little to none.

I am creating an application for my final year project at University
what displays football rumours posted by different users.

My problem
is as follows:
I have one screen that displays each individual rumour, using a while
loop in PHP I am able to get each rumour from the database and display
them correctly. However I want to be able to click on one rumour which
then displays this rumour in a different screen, along with options to
reply/share etc. However I do not know how to tell which rumour has
been clicked on.

Snippets of my code:
All rumours page: 

    <?php 
        $q1 = "SELECT * FROM tblrumours;"; 
        $r1 = mysql_query($q1); 
        while( $row1 = mysql_fetch_assoc($r1) ){ 
?> 
    <a class="rumourTag submit" id="<?php echo $row1['rumourID']; ?>"> 
            <div class='oneRumour'> 
            <div class='standardBubble'> 
                    <p> 
                    <?php 
                            $userID = $row1['userID']; 
                            $q2 = "SELECT * FROM tblusers WHERE userID = $userID;"; 
                            $r2 = mysql_query($q2); 
                            while( $row2 = mysql_fetch_array($r2) ){ 
                                    $username = $row2['username']; 
                                    $teamID = $row2['teamID']; 
                            } 
                            $q5 = "SELECT * FROM tblteams WHERE teamID = $teamID;"; 
                            $r5 = mysql_query($q5); 
                            while( $row5 = mysql_fetch_array($r5) ){ 
                                    echo "<img src='img/".$row5['teamPicture']."' alt='' 
    class='teamImg' />"; 
                            } 
                    ?> 
                    <span class='username'> 
                    <?php 
                            echo $username; 
                    ?> 
                    </span> 
                    <br/> 
                    <span class='rumourMsg'><?php echo $row1['rumourText']; ?></ 
    span> 
            </p> 
        </div>
    </a>

SINGLE RUMOURS PAGE: 

<?php 
       $q1 = "SELECT * FROM tblrumours WHERE rumourID = 1;"; /* NEED 
TO SELECT WHERE RUMOUR ID IS THE ONE THAT IS CLICKED */ 
        $r1 = mysql_query($q1); 
        while( $row1 = mysql_fetch_array($r1) ){ 
?>..........

I have tried using Session variables, storing the ID’s in an array,
creating a separate php file for the single rumour page, and all to no
avail. I am guessing I have to use AJAX in some way, but I have no
idea where to even begin. Any help is greatly appreciated!
Thanks!

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1 Answer

  1. Editorial Team

    If you need to click on a rumour to see more details about it, you could always output in the HTML a unique value used to reference that rumour in the DB.

    e.g. have <span class='rumourMsg' id='rumourName'> where rumourName is a unique value stored in your database to reference that rumour. Then when a user clicks to see more details, you can make a request to the PHP page with that value and return the content.

    e.g. rumourDetails?rumourName=uniqueRumourName

    (make sure to escape all your data properly to avoid SQL injection vulnerabilities.)

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