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Home/ Questions/Q 8719219
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T06:44:27+00:00 2026-06-13T06:44:27+00:00

I am having some trouble converting a php pregmatch to java. I thought I

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I am having some trouble converting a php pregmatch to java. I thought I had it all correct but it doesn’t seem to be working. Here is the code:

Original PHP:

/* Pattern for 44 Character UUID */
$pattern = "([0-9A-F\-]{44})";
if (preg_match($pattern,$content)){
                /*DO ACTION*/
            }

My Java code:

final String pattern = "([0-9A-F\\-]{44})";
    public static boolean pregMatch(String pattern, String content) {
            Pattern p = Pattern.compile(pattern);
            Matcher m = p.matcher(content);
            boolean b = m.matches();
            return b;
        }
if (pregMatch(pattern, line)) {
                        //DO ACTION
                    }

So my test input is:
DBA40365-7346-4DB4-A2CF-52ECA8C64091-0

Using a series of System.outs I get that b = false.

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  1. Editorial Team
    Editorial Team
    2026-06-13T06:44:29+00:00Added an answer on June 13, 2026 at 6:44 am

    To implement a function as you did in your code:

    final String pattern = "[0-9A-F\\-]{44}";
    public static boolean pregMatch(String pattern, String content) {
        return content.matches(pattern);
    }
    

    And then you can call it as:

    if (pregMatch(pattern, line)) {
        //DO ACTION
    }
    

    You don’t need the parenthesis in your pattern because that just creates a match group, which you are not using. If you need access to back references, you would need the parenthesis an a more advanced regex code using Pattern and Matcher classes.

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