Question

I am having the problem with MySQL ROUND() Function.
Here it is:

When I do this:

SELECT ROUND(7/2) as avg FROM bla blah

avg is 4

When I do this:

 SELECT ROUND(SUM(marks)/COUNT(marks)) as avg

avg is 3
Note: SUM(marks) on its own gives 7 and COUNT(marks) gives 2 which as far as I understand
ROUND(SUM(marks)/COUNT(marks)) should be equal to ROUND(7/2)

What is the problem?

Answer 1

You might use CEILING (same as ROUND except it always rounds to the bigger nearest integer)

SELECT CEILING(SUM(marks)/COUNT(marks)) as avg

should yield the result you want for the requirements specified in the question.