Question

I am having the x-value and corresponding counts in a file. I read that as list of tuples in the following form

dat = [(0.02, 1), 
(0.0211, 1), 
(0.021, 1), 
(0.023, 1), 
(0.0251, 1), 
(0.12, 2), 
(0.141, 1), 
(0.14, 3), 
(0.171, 1), 
(0.462, 9),
(0.467, 10),
(0.478, 15), 
(0.804, 20), 
(0.815, 31), 
(0.815, 24),
(2.72, 164), 
(2.78, 147), 
(2.8, 128),
(5.78, 6), 
(5.83, 1), 
(5.8603, 1),
(5.94, 17), 
(8.63, 3), 
(8.87, 5),  
(18.601, 1), 
(19.0, 7), 
(21.0, 2), 
(22.0, 4)]

How to convert these into equal interval counts. For example, an intervals with 0.2 increments.

x    count
0    0
0.5  12
1.0  75
1.5  0
2.0  0
2.5  0
3.0  439
... 

Answer 1

An approach with pandas:

In [74]: df = pd.DataFrame.from_records(dat).set_index(0)

In [75]: counts = df.groupby(lambda x: floor(x / 0.5) * 0.5).count()

In [76]: counts
Out[76]: 
       1
0.0   12
0.5    3
2.5    3
5.5    4
8.5    2
18.5   1
19.0   1
21.0   1
22.0   1

You can fill the intervals with zero counts:

In [77]: counts.reindex(np.arange(0, 22, 0.5)).fillna(0)
Out[73]: 
       1
0.0   12
0.5    3
1.0    0
1.5    0
2.0    0
2.5    3
3.0    0
3.5    0
4.0    0

etc ...