Question

I am having trouble creating a SQL table with a PHP variable.

Let’s say $tbl_date = “data”;

mysql_query('CREATE TABLE '.$tbl_date.'
(
Test varchar(15),
Yes varchar(15),
Very int
)');

It doesn’t create the table.

Answer 1

It looks like it’s not working because your table name is not in the quotes. Try this:

mysql_query('CREATE TABLE `'.$tbl_date.'`
(
`Test` varchar(15),
`Yes` varchar(15),
`Very` int
)');

And the same applies for field names.
Also try this, it’s easier to read by humans:

mysql_query("CREATE TABLE `{$tbl_date}`
(
`Test` varchar(15),
`Yes` varchar(15),
`Very` int
)");

Please note different types of quotes:
– single quotes and double quotes for building some string (eg.SQL query) in PHP
– back quotes used specially as a part of SQL query for table names and column names