Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7458619
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 29, 20262026-05-29T13:28:18+00:00 2026-05-29T13:28:18+00:00

I am having trouble figuring out how to make text found using glob into

  • 0

I am having trouble figuring out how to make text found using glob into a link. I am sure it is something really simple, such as adding an <a> tag to the echo line, but I cannot figure out where in the code to put this.

Here is my current code:

 $directory = "*.xls";
 $directory = (!strstr($directory,"*") || $directory =="./" ) ? $directory."*" : $directory;
 $files = glob($directory);
 for( $i=0; $i < sizeof( $files); $i++)
 {
     echo basename($files[$i])."<br/>\n";
 }
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-29T13:28:18+00:00Added an answer on May 29, 2026 at 1:28 pm

    Try this:

    $file = basename($files[$i]);
    echo '<a href="' . $file . '">' . $file . '</a>' . "<br />\n";
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm having trouble figuring out how to make a GET request using RestSharp on
I'm having some trouble figuring out how to make a reference to a subroutine
I'm having a bit of trouble figuring out how to make this repository pattern
I'm having some trouble figuring out how to make the page load architecture of
I'm having trouble figuring out the proper way to update nested data using Google
I am having trouble figuring out how to make soap requests. First I load
im having trouble figuring out how to bind mouseout() to my entire nav bar
I'm having trouble figuring out how to get the testing framework set up and
I'm having trouble figuring out how to access a cookie from a compiled object.
I'm having trouble figuring out how to delete a set of records when a

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.