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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T05:36:20+00:00 2026-05-20T05:36:20+00:00

I am having trouble figuring out how to prove that t(n) = sqrt(31n +

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I am having trouble figuring out how to prove that

t(n) = sqrt(31n + 12n log n + 57)

is

O(sqrt(n) log n)

I haven’t had to deal with square root’s in big O notation yet so I am having lots of trouble with this! Any help is greatly appreciated 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-20T05:36:21+00:00Added an answer on May 20, 2026 at 5:36 am

    Big O notation is about how algorithm characteristics (clock time taken, memory use, processing time) grow with the size of the problem.

    Constant factors get discarded because they don’t affect how the value scales.

    Minor terms also get discarded because they end up having next to no effect.

    So your original equation

    sqrt(31n + 12nlogn + 57)
    

    immediately simplifies to

    sqrt(n log n)
    

    Square roots distribute, like other kinds of multiplication and division, so this can be straightforwardedly converted to:

    sqrt(n) sqrt(log n)
    

    Since logs convert multiplication into addition (this is why slide rules work), this becomes:

    sqrt(n) log (n/2)
    

    Again, we discard constants, because we’re interested in the class of behaviour

    sqrt(n) log n
    

    And, we have the answer.

    Update

    As has been correctly pointed out,

    sqrt(n) sqrt(log n)
    

    does not become

    sqrt(n) log (n/2)
    

    So the end of my derivation is wrong.

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