Question

I am having trouble finding pairs in a string of size five. So therefore, there can only be two pairs. For every pair that I have found, I should increase the score by 2 points.
Here is what I have so far, but it is incorrect.

  String  temp = "4 5 4 3 3";
  String  tempLine = temp.replaceAll(" ", "");
  String[]  hand = temp.split(" ");
        for(int i = 0; i < hand.length; i++)
                  {

                      if(hand[i].equals(tempLine.substring(0, 1)) && i !=0 )
                          score += 1;
                      if(hand[i].equals(tempLine.substring(1, 2)) && i != 1 )
                          score += 1;
                      if(hand[i].equals(tempLine.substring(2, 3)) && i!= 2 )
                          score += 1;
                      if(hand[i].equals(tempLine.substring(3, 4)) && i!= 3)
                          score += 1;
                      if(hand[i].equals(tempLine.substring(4)) && i != 4)
                          score += 1;

                  }

EDIT: I am trying to find pairs in the hand that have similar value, for example 4 would be one pair found in this hand

Answer 1

I think this fits what you’re trying to do.

char[] hand = {'a','b','c','b','c'};
/* sort the hand to ensure pairs are next to each other */
for(int x=0;x<hand.length - 1;x++){
    for(int y=(x+1);y<hand.length;y++){
        if((int)hand[x] > (int)hand[y]){
            char temp = hand[y];
            hand[y] = hand[x];
            hand[x] = temp;
        }
    }
}
int score = 0;
for(int x=0;x<hand.length - 1;x++){
    if(hand[x] == hand[x + 1]){
        score++;
        /*if you want to make sure you only get pairs
          add an "x++;" that way it'll skip over the 
          letter you just tested*/
    }
}