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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T15:08:02+00:00 2026-06-11T15:08:02+00:00

I am having trouble trying to understand how logical operators work in C. I

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I am having trouble trying to understand how logical operators work in C. I already understand how the bit-level operators work, and I also know that logical operators treat nonzero arguments as representing TRUE and zero arguments as representing FALSE

But say we have 0x65 && 0x55. I do not understand why and how this operations gives 0x01.

I tried to convert it to binary, but I cannot figure out how it works

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  1. Editorial Team
    Editorial Team
    2026-06-11T15:08:03+00:00Added an answer on June 11, 2026 at 3:08 pm

    The && is a logical AND (as opposed to &, which is a bitwise AND). It cares only that its operands as zero/non-zero values. Zeros are considered false, while non-zeros are treated as true.

    In your case, both operands are non-zero, hence they are treated as true, resulting in a result that is true as well. C represents true as 1, explaining the overall result of your operation.

    If you change the operation to &, you would get a bitwise operation. 0x65 & 0x55 will give you a result of 0x45.

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