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Home/ Questions/Q 726465
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T06:27:19+00:00 2026-05-14T06:27:19+00:00

I am having trouble understanding the following article: http://www.ibm.com/developerworks/java/library/j-jtp01255.html Under, Generics are not covariant

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I am having trouble understanding the following article:
http://www.ibm.com/developerworks/java/library/j-jtp01255.html

Under,

Generics are not covariant

the author states,

Because ln is a List, adding a
Float to it seems perfectly legal. But
if ln were aliased with li, then it
would break the type-safety promise
implicit in the definition of li —
that it is a list of integers, which
is why generic types cannot be
covariant.

I can’t understand the part where it says
"if ln were aliased with li". What does the author means by alias?(reference?). The code snippet above the quoted line seems to illustrate WHAT is illegal in java and not WHY. It would be very helpful to me if somebody could explain with an example.
Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-14T06:27:19+00:00Added an answer on May 14, 2026 at 6:27 am
    List<Integer> li = new ArrayList<Integer>();
    List<Number> ln = li; // illegal
    ln.add(new Float(3.1415));
    

    In Java, Integer inherits from Number(java.lang.Number), so intuitively, anything that is an Integer(java.lang.Integer) is also a number, but what that article points out is that with generics it does not work that way, because considering that example, you could end up putting a float (which is a Number) into a List<Integer>, which is illegal because a float is not an integer.

    Conclusion: Generics are not covariant.

    Note: I recommend you read Effective Java (2nd Edition) Chapter 5: Generics.

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