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Home/ Questions/Q 4083478
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Editorial Team
  • 0
Editorial Team
Asked: May 20, 20262026-05-20T18:19:04+00:00 2026-05-20T18:19:04+00:00

I am having trouble with $this selector for JQuery. This is doing nothing. The

  • 0

I am having trouble with $this selector for JQuery. This is doing nothing. The fundamental core of the script is not failing though.

$(this).css("background-image", 
"url(http://www.divethegap.com/update/z-images/diving-trips/tabs/bases-z.png)");

Any ideas why it does not work? I have tried the same effect using class.

THE FULL CODE (as requested)
http://jsfiddle.net/mcxez/1/:

Markup:

<a href="?accommodation" style="background-position:-15px top;" 
   onclick="inload('?accommodation'); return false">Accommodation</a>

<a href="?travel" style="background-position:-15px top;" 
   onclick="inload('?travel'); return false">Travel</a>

js:

function inload(thelink) {
    $('.TABbase').click(function(){
        $(this).css("background-image", 
            "url(http://www.divethegap.com/update/z-images/diving-trips/tabs/bases-z.png)"); 
    });

  return false;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T18:19:05+00:00Added an answer on May 20, 2026 at 6:19 pm

    Here is the revised HTML

    <a href="?accommodation" style="background-position:-15px top;" data-href="?accomodation" class="my_class">Accommodation</a>
    <a class="my_class" href="?travel" style="background-position:-15px top;" data-href="?travel" >Travel</a>
    

    Here is the javascript

    $(document).ready(function(){
      $(".my_class").click(function(){
        $(this).css("background-image", "url(http://www.divethegap.com/update/z-images/diving-trips/tabs/bases-z.png)");
        return false;
      });
    });
    
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