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Home/ Questions/Q 8234185
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T18:23:33+00:00 2026-06-07T18:23:33+00:00

I am hitting on a corner case in pandas. I am trying to use

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I am hitting on a corner case in pandas. I am trying to use the agg fn but without doing a groupby. Say I want an aggregation on the entire dataframe, i.e.

from pandas import *
DF = DataFrame( randn(5,3), index = list( "ABCDE"), columns = list("abc") )
DF.groupby([]).agg({'a' : np.sum, 'b' : np.mean } ) # <--- does not work

And DF.agg( {'a' ... } ) does not work either.

My workaround is to do DF['Total'] = 'Total' then do a DF.groupby(['Total']) but this seems a bit artificial.

Has anyone got a cleaner solution?

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  1. Editorial Team
    Editorial Team
    2026-06-07T18:23:35+00:00Added an answer on June 7, 2026 at 6:23 pm

    It’s not so great either, but for this case, if you pass a function returning True at least it wouldn’t require changing df:

    >>> from pandas import *
    >>> df = DataFrame( np.random.randn(5,3), index = list( "ABCDE"), columns = list("abc") )
    >>> df.groupby(lambda x: True).agg({'a' : np.sum, 'b' : np.mean } )
                 a         b
    True  1.836649 -0.692655
    >>> 
    >>> df['total'] = 'total'
    >>> df.groupby(['total']).agg({'a' : np.sum, 'b' : np.mean } ) 
                  a         b
    total                    
    total  1.836649 -0.692655
    

    You could use various builtins instead of lambda x: True but they’re less explicit and only work accidentally.

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