Question

I am implementing 8bit adder in python.
Here is the adder function definition:

def add8(a0,a1,a2,a3,a4,a5,a6,a7,b0,b1,b2,b3,b4,b5,b6,b7,c0):

All function parameters are boolean.
I have implemented function that converts int into binary:

def intTObin8(num):
    bits = [False]*8
    i = 7
    while num >= 1:
        if num % 2 == 1:
            bits[i] = True
        else:
            bits[i] = False
        i = i - 1
        num /= 2
    print bits
    return [bits[x] for x in range(0,8)]

I want this function to return 8 bits. And to use this two functions as follows:

add8(intTObin8(1),intTObin8(1),0)

So the question is: How to pass 8 parameters using one function?

Answer 1

One way to do this:

add8(*(intTObin8(1) + intTObin8(1) + [0]))

Which concatenates the lists and then passes it as an argument to add8.

If you a doing this a few times you could put it in another function:

def add8_from_bin8(a,b,c0):
    add8(*(a + b + [c0]))

add8_from_bin8(intTObin8(1), intTObin8(1), 0)