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Editorial Team
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Asked: 2026-06-07T13:34:11+00:00

I am implementing a Restful Web Service using Jersey. I want to show index.jsp

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I am implementing a Restful Web Service using Jersey. I want to show index.jsp as welcome page.

<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
   "http://www.w3.org/TR/html4/loose.dtd">

<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <title>Rest Page</title>
    </head>
    <body>
        <h1>Rest is working!</h1>
    </body>
</html>

It works fine when I use this code in my web.xml: 

<servlet-mapping>
    <servlet-name>Jersey REST Service</servlet-name>
    <url-pattern>/whatever/*</url-pattern>
  </servlet-mapping>

  <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>

The problem is when the user-pattern is like this:

<url-pattern>/*</url-pattern>

Everything works fine except welcome page. I appreciate Any help.

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1 Answer

  1. Editorial Team

    I found an alternative way to do this. instead of using index.jsp, I can use a class like:

    @Path("/")
public class Hello {

    // This method is called if HTML is request
    @GET
    @Produces(MediaType.TEXT_HTML)
    public String sayHtmlHello() {
       return "<html> " + "<title>" + "Rest Page" + "</title>"
          + "<body><h1>" + "REST is Working!" + "</body></h1>" + "</html> ";
}

    In web.xml I do not need to use:

    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>

    And it works fine with:

    <url-pattern>/*</url-pattern>
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