Question

I am implementing an application with get the response from service and show to view.I have used two text views for get the two types of responses from service.When i click on a text view i am getting response is verry late then the UI is hanging in this time i would like to show busy progress dialog on view and when i got response then i would like to close that progress dialog.i am updating view with response to list view.
I have implemented code as follows:

 textView1.setOnClickListener(new OnClickListener() {

@Override
public void onClick(View v) {
waitProgreess = ProgressDialog.show(ShoutGetMsgsScreen.this, "Please wait", "Loading...");
 resultFromService = new ParseXml().convertMessages(new Model().getMessages("0"));
lst.setAdapter(new CustomeAdapter(ShoutGetMsgsScreen.this, resultShoutMessage));

    if(resultFromService .size()>5){

                    waitProgreess.dismiss();
                }
   }
        }); 

from the above implementation how can i show a progress dialog and when the view is updated then how can i close progress dialog?

please any body help me…

Answer 1

private class GetDATA extends AsyncTask<Void, Void, Void>
{
    ProgressDialog pd;
    @Override
    protected void onPreExecute() {
        pd = ProgressDialog.show(Activity.this, "", getString("loding..."), true, false);
        super.onPreExecute();
    }

    @Override
    protected Void doInBackground(Void... params) {


resultFromService = new ParseXml().convertMessages(new Model().getMessages("0"));
return null;
    }

    @Override
    protected void onPostExecute(Void result) {
        super.onPostExecute(result);
        if (pd != null && pd.isShowing())
            pd.dismiss();
        }

lst.setAdapter(new CustomeAdapter(ShoutGetMsgsScreen.this, resultShoutMessage));

    }
}

call like that :-

(new GetDATA()).execute();