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Home/ Questions/Q 4340420
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T11:20:48+00:00 2026-05-21T11:20:48+00:00

I am in the middle of creating some generic class. And I create three

  • 0

I am in the middle of creating some generic class.

And I create three view-controller and I create a enum

typedef enum Type {
    type1,
    type2,
    type3,
} Type;

and for three different type I need to use different view-controllers subclass.
But the user feels like one. (what I mean is I can provided it with an interface in that interface class we need to decide which controller used).

I try like this,
I create a class and override the init method like follows,

- (id)initWithReaderType:(ReaderType )readerType    {

        switch (readerType) {
            case 0: {
                Slider *slider = [[Slider alloc] init];
                return slider;
            }
            case 1: {
                //use other controller
                break;
            }
            default:    {
                NSLog(@"Exception on Initialization : Un Recognized Reader Type");
                break;
            }
        }

    return nil;
}

But it returns as id object, So I can’t use it as a view-controller object and I don’t get access to the properties and methods of that controller class.

How Can I achieve this?

thanks in advance….

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  1. Editorial Team
    Editorial Team
    2026-05-21T11:20:48+00:00Added an answer on May 21, 2026 at 11:20 am

    You can just cast the id (pointer) to an UIViewController (or any of it’s subclasses).

    id result = [self initWithReaderType:type1];
    // Check if we can cast.
    if ([result isKindOfClass[UIViewController class]]) {
       UIViewController *viewController = (UIViewController *)[self initWithReaderType:type1];
    }
    

    You can change the UIViewController to your own class.

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