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Home/ Questions/Q 9254683
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T11:32:01+00:00 2026-06-18T11:32:01+00:00

I am in the middle of migrating all my bash scripts to Ruby. I

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I am in the middle of migrating all my bash scripts to Ruby. I am finding Ruby to be awesome however am stuck with a small problem. I am trying to move this script (basically find all logs older than x hours and process them). The Bash script looks something like this

find /var/log/myservice.log.* -mmin -120  -exec cp {} /home/myhomedir/mylogs/ \;

Of course I can loop through all the files, manually apply File.mtime on them and then identify the ones. However I want to understand if there is a much cleaner, one-liner to do this efficiently.

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  1. Editorial Team
    Editorial Team
    2026-06-18T11:32:02+00:00Added an answer on June 18, 2026 at 11:32 am

    One liner:

    require 'fileutils'; Dir.glob("/var/log/myservice.log.*").each{|f| FileUtils.cp(f, '/home/myhomedir/mylogs/') if File.mtime(f) < (Time.now - (60*120)) }
    

    Though I would prefer it spelled out a bit more:

    require 'fileutils'
    Dir.glob("/var/log/myservice.log.*").
      select{|f| File.mtime(f) < (Time.now - (60*120)) }.
      each{|f| FileUtils.cp(f, '/home/myhomedir/mylogs/') }
    
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