Question

I am just a noob on reg exp and I am trying to learn them. If I have a file name like this:

myfile(1).jpg or myfile(21).jpg

How can I extract with an reg exp (php or javascript) the file name [myfile], bracket numbering [1] and extension [jpg]?

Answer 1

Try this regex:

/^(.*?)(?:\((\d+)\))?\.(.+)$/

$1 variable will contain the filename.
$2 variable will contain the numbering (if it is available or else it will be undefined or null).
$3 variable will contain the extension.