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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T06:11:33+00:00 2026-05-20T06:11:33+00:00

I am just doing a research on a project and came across a problem.

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I am just doing a research on a project and came across a problem. I would be very grateful if anybody could help me out with this. Consider the figure below:

enter image description here

Two dots joined by a line results in only one diagram, three dots joined by single lines also results in one figure no matter how you join the dots, the result is the same. But as we increase the dots there are different possibilities, as seen with four dots.

Is there a formula for counting the number of unlabeled trees that can be formed from a set of nodes?

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  1. Editorial Team
    Editorial Team
    2026-05-20T06:11:34+00:00Added an answer on May 20, 2026 at 6:11 am

    This is non-isomorphic graph count problem.

    For general case, there are 2^(n2) non-isomorphic graphs on n vertices where (n2) is binomial coefficient “n above 2”.

    However that may give you also some extra graphs depending on which graphs are considered the same (you also were not 100% clear which graphs do apply).

    See this paper.
    And this article on MathWorld.

    EDIT: In case you want to count labeled trees only the formula is n^(n-2).

    Wikipedia.

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