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Home/ Questions/Q 3603724
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T20:54:28+00:00 2026-05-18T20:54:28+00:00

I am just getting into jQuery so please forgive this maby stupid question, but

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I am just getting into jQuery so please forgive this maby stupid question, but I encountert the following:

$('#pb_inner').css('width',data + '%');

this code works fine. However I wonder why I can’t do the following?

$('#pb_inner').style.width=data + '%';
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  1. Editorial Team
    Editorial Team
    2026-05-18T20:54:28+00:00Added an answer on May 18, 2026 at 8:54 pm

    Because $('#pb_inner') returns an array like jQuery object. A collection, not a single object (and even then, it would be another jQuery object):

    From the docs:

    (…), jQuery() — which can also be written as $() — searches through the DOM for any elements that match the provided selector and creates a new jQuery object that references these elements.


    You would have to use get:

    $('#pb_inner').get(0).style.width=data + '%';
    

    The .get() method grants us access to the DOM nodes underlying each jQuery object

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