Question

I am just getting started with MySQL queries, and have been fighting this for days with no luck finding a solution, so here goes.

Table structure as follows:

|         ID         |   TAG
| 111909684134416384 | WesternU
| 111909684134416384 | ldnon
| 111910470428008448 | ldnont
| 111910470428008448 | fb
| 111910605249712128 | LTC
| 111910605249712128 | ldnon
| 111911886139826176 | ldnont
| 111911886139826176 | WesternU

I would like to select, count, and list the TAG(s) where one TAG of the same ID has ‘ldnont’ or ‘ldnon’ listed.

Essentially, from this data set, I would like to list and count:

WesternU (2)
fb (1)
LTC (1)

I’ve been able to select and count, but only the first row of rows with duplicate ID.
Thank-you in advance for any assistance.

Answer 1

 SELECT Tag, COUNT(*) FROM JodyTable 
      WHERE Tag NOT IN ('ldnon', 'ldnont')
         AND ID IN (SELECT ID FROM JodyTable WHERE Tag IN ('ldnon', 'ldnont'))