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Home/ Questions/Q 748763
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T14:21:26+00:00 2026-05-14T14:21:26+00:00

I am just making sure I understand this concept correctly. With the * operator,

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I am just making sure I understand this concept correctly. With the * operator, I make a new variable, which is allocated a place in memory. So as to not unnecessarily duplicate variables and their values, the & operator is used in passing values to methods and such and it actually points to the original instance of the variable, as opposed to making new copies…Is that right? It is obviously a shallow understanding, but I just want to make sure I am not getting them mixed up. Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-14T14:21:27+00:00Added an answer on May 14, 2026 at 2:21 pm

    Not quite. You’re confusing a * appearing in a type-name (used to define a variable), with the * operator.

    int main() {
        int i;    // i is an int
        int *p;   // this is a * in a type-name. It means p is a pointer-to-int
        p = &i;   // use & operator to get a pointer to i, assign that to p.
        *p = 3;   // use * operator to "dereference" p, meaning 3 is assigned to i.
    }
    
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