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Home/ Questions/Q 7933123
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T21:13:54+00:00 2026-06-03T21:13:54+00:00

I am just trying to write a simple script that verifies the username and

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I am just trying to write a simple script that verifies the username and password of a user that has attempted to login…and then starts a session. However, I am running into some trouble.

When I try to run the script below, SUCCESS does not print out. As if the username and password is incorrect, however, I know for a fact that the username and passwords entered are, in fact, correct.

$username = $_POST['username'];
$password = $_POST['password'];

$result = mysql_query("SELECT * FROM users WHERE username='.$username.' AND password='.$password.'");

while($row = mysql_fetch_array($result)){
    echo 'SUCCESS';
}

When I try to run the script below however, success prints out twice (which is the number of sample users I have in my db so far), which is correct.

I am guess I have a problem with the AND mySQL query above, however, it seems correct to me… is there a problem with my first query above? if not, than what else might be the problem?

$username = $_POST['username'];
$password = $_POST['password'];

$result = mysql_query("SELECT * FROM users");

while($row = mysql_fetch_array($result)){
    echo 'SUCCESS';
}
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  1. Editorial Team
    Editorial Team
    2026-06-03T21:13:56+00:00Added an answer on June 3, 2026 at 9:13 pm

    You’re parsing variables, not concatenating them, you don’t need the ..

    "SELECT * FROM users WHERE username='$username' AND password='$password'"
    
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