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Editorial Team
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Asked: 2026-06-02T06:32:28+00:00

I am launching requests to a web service using Groovy/XmlSlurper : new XmlSlurper().parse(http://en.wikipedia.org/w/api.php?action=…) I

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I am launching requests to a web service using Groovy/XmlSlurper:

new XmlSlurper().parse("http://en.wikipedia.org/w/api.php?action=...")

I would like to set the user agent to let the website know what project the requests are from.

How to set the user agent?

  • XMLSlurper’s constructors do not have anything like this.
  • The setProperty method sounds interesting but Google does not lead to anything related to UA.
  • I would rather avoid changing the code to abandon XmlSlurper in favor of another library.
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1 Answer

  1. Editorial Team

    Looks like Groovy uses the JVM’s default SAX parser to connect to the input stream and perform the initial parsing. I saw this answer on SO that might help – all you need to do is set this before your call to the slurper to make it happen:

    System.setProperty("http.agent", "my-agent-name");

    P.S. This is just a guess – hope it helps.

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