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Home/ Questions/Q 7745151
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T09:56:30+00:00 2026-06-01T09:56:30+00:00

I am learning about arrays, and basically I have an array that collects a

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I am learning about arrays, and basically I have an array that collects a last name, first name, and score.

I need to write a compareTo method that will compare the last name and then the first name so the list could be sorted alphabetically starting with the last names, and then if two people have the same last name then it will sort the first name.

I’m confused, because all of the information in my book is comparing numbers, not objects and Strings.

Here is what I have coded so far. I know it’s wrong but it at least explains what I think I’m doing:

public int compare(Object obj) // creating a method to compare 
{   
    Student s = (Student) obj; // creating a student object

    // I guess here I'm telling it to compare the last names?
    int studentCompare = this.lastName.compareTo(s.getLastName()); 

    if (studentCompare != 0)
        return studentCompare;
    else 
    {
        if (this.getLastName() < s.getLastName())
            return - 1;

        if (this.getLastName() > s.getLastName())
            return 1;
    }
    return 0;
}

I know the < and > symbols are wrong, but like I said my book only shows you how to use the compareTo.

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  1. Editorial Team
    Editorial Team
    2026-06-01T09:56:31+00:00Added an answer on June 1, 2026 at 9:56 am

    This is the right way to compare strings:

    int studentCompare = this.lastName.compareTo(s.getLastName()); 
    

    This won’t even compile:

    if (this.getLastName() < s.getLastName())
    

    Use
    if (this.getLastName().compareTo(s.getLastName()) < 0) instead.

    So to compare fist/last name order you need:

    int d = getFirstName().compareTo(s.getFirstName());
    if (d == 0)
        d = getLastName().compareTo(s.getLastName());
    return d;
    
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