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Home/ Questions/Q 6319123
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T15:45:00+00:00 2026-05-24T15:45:00+00:00

I am learning about streaming. The standard streams provide the << operator which can

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I am learning about streaming. The standard streams provide the << operator which can be declared as:

ostream& operator<<(stream& os, CLASS& rc);  

Why is it impossible to declare it as this?

ostream& operator>>(CLASS& rc, stream& os); 

Then I may be able to do something like:

rc.something >> os;

as part of its implementation.


Edit as people have helped me learn more about this, I am thankful.

However I am stuck at how to implement actually it.

I have tried

ostream& operator >> (const SomeClass& refToCls, stream& os)
{
   refToCls.iVar >> os;
   return os;
}

but it fails. How can I fix it?

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  1. Editorial Team
    Editorial Team
    2026-05-24T15:45:02+00:00Added an answer on May 24, 2026 at 3:45 pm

    In fact it’s possible to define

    ostream& operator>>(CLASS& rc, ostream& os);
    

    But then you must chain it like this:

    a >> (b >> (c >> str));
    

    The >> operator is left-associative, so by default this:

    a >> b >> c >> str;
    

    is equivalent to:

    ((a >> b) >> c) >> str;
    

    which has a wrong meaning.

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