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Home/ Questions/Q 3404576
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T05:23:59+00:00 2026-05-18T05:23:59+00:00

I am learning javascript sample from this page, http://nofunc.org/AJAX_Star_Rating my questions are (1), for

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I am learning javascript sample from this page,

http://nofunc.org/AJAX_Star_Rating

my questions are (1),

for function function XY(e,v), it has two input parameters e and v, but it is called with only one parameter x=XY(e), how does it work?

question (2), I am confused about what this function XY is doing below, especially confused about the grammar {'X':e.pageX,'Y':e.pageY} and v?o[v]:o, could anyone explain what do they mean please?

var o=agent('msie')?{'X':event.clientX+document.documentElement.scrollLeft,'Y':event.clientY+document.documentElement.scrollTop}:{'X':e.pageX,'Y':e.pageY}; return(v?o[v]:o); }

thanks in advance,
George

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  1. Editorial Team
    Editorial Team
    2026-05-18T05:24:00+00:00Added an answer on May 18, 2026 at 5:24 am

    function XY(e,v) is an event handler. First argument is the event object passed to the function, second is the element affected. The function is called automatically by Javascript when the relevant event is triggered.

    {'X':e:pageX, 'Y':e:pageY} are just key-value pairs. Essentially, an “array” with identifiers for each element and a value corresponding to that identifier. Strictly speaking, Javascript doesn’t have “arrays”. They’re called objects. The identifiers are called properties.

    v?o[v]:o translates to if (v) return o[v]; else return o; Ternary expressions, as they are known, also appear in the last line. if (agent('msie')) var o={'X':event...}; else var o={'X':e.pageX,...};

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