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Asked: 2026-05-14T06:36:25+00:00

I am learning php, trying to use the fopen() function. The php file I

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I am learning php, trying to use the fopen() function.
The php file I am coding is in this directory /domains/xxxxx.com.au/public_html/phpfile.php
What path do I specify for the file to be opened, the example I am looking at is based on a server on a pc where this is the file path $filename = "c:/newfile.txt"; not an online server.

UPDATE!

This is the whole script, I have the file location correct, now the4 script is returning “couldnt create the file” does this have something to do with ther permission of the folder location of the file?

   <?php
$filename = "/domains/xxxxxxxx.com.au/public_html/newfile.txt";
$newfile = @fopen($filename, "w+") or die ("couldnt create the file");
fclose($newfile);
$msg = "<p>File Created</p>";
?>

<HTML>
<HEAD>
</HEAD>
<BODY>

<? echo "$msg" ?>

</BODY>
</HTML>
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1 Answer

  1. Editorial Team

    Assuming that your php file is inside the public_html too, you could use :

    $fp = fopen( "newfile.txt", "rt" );

    Or, giving the full path :

    $fp = fopen( "/domains/xxxxx.com.au/public_html/newfile.txt", "rt" );

    This will open it if it already exists.

    Refer to this for further details of opening flags.

    UPDATE:
    You can even use the is_writable/is_readable function to check file access before trying to open it.

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